Optimal. Leaf size=543 \[ \frac {a^3 (c+d x)^{1+m}}{d (1+m)}-\frac {3 a b^2 (c+d x)^{1+m}}{2 d (1+m)}+\frac {3^{-1-m} b^3 e^{3 e-\frac {3 c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {3 f (c+d x)}{d}\right )}{8 f}+\frac {3\ 2^{-3-m} a b^2 e^{2 e-\frac {2 c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {2 f (c+d x)}{d}\right )}{f}+\frac {3 a^2 b e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {f (c+d x)}{d}\right )}{2 f}-\frac {3 b^3 e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {f (c+d x)}{d}\right )}{8 f}+\frac {3 a^2 b e^{-e+\frac {c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {f (c+d x)}{d}\right )}{2 f}-\frac {3 b^3 e^{-e+\frac {c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {f (c+d x)}{d}\right )}{8 f}-\frac {3\ 2^{-3-m} a b^2 e^{-2 e+\frac {2 c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {2 f (c+d x)}{d}\right )}{f}+\frac {3^{-1-m} b^3 e^{-3 e+\frac {3 c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {3 f (c+d x)}{d}\right )}{8 f} \]
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Rubi [A]
time = 0.56, antiderivative size = 543, normalized size of antiderivative = 1.00, number of steps
used = 18, number of rules used = 5, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3398, 3389,
2212, 3393, 3388} \begin {gather*} \frac {3 a^2 b e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,-\frac {f (c+d x)}{d}\right )}{2 f}+\frac {3 a^2 b e^{\frac {c f}{d}-e} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,\frac {f (c+d x)}{d}\right )}{2 f}+\frac {3 a b^2 2^{-m-3} e^{2 e-\frac {2 c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,-\frac {2 f (c+d x)}{d}\right )}{f}-\frac {3 a b^2 2^{-m-3} e^{\frac {2 c f}{d}-2 e} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,\frac {2 f (c+d x)}{d}\right )}{f}+\frac {b^3 3^{-m-1} e^{3 e-\frac {3 c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,-\frac {3 f (c+d x)}{d}\right )}{8 f}-\frac {3 b^3 e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,-\frac {f (c+d x)}{d}\right )}{8 f}-\frac {3 b^3 e^{\frac {c f}{d}-e} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,\frac {f (c+d x)}{d}\right )}{8 f}+\frac {b^3 3^{-m-1} e^{\frac {3 c f}{d}-3 e} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \text {Gamma}\left (m+1,\frac {3 f (c+d x)}{d}\right )}{8 f}+\frac {a^3 (c+d x)^{m+1}}{d (m+1)}-\frac {3 a b^2 (c+d x)^{m+1}}{2 d (m+1)} \end {gather*}
Antiderivative was successfully verified.
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Rule 2212
Rule 3388
Rule 3389
Rule 3393
Rule 3398
Rubi steps
\begin {align*} \int (c+d x)^m (a+b \sinh (e+f x))^3 \, dx &=\int \left (a^3 (c+d x)^m+3 a^2 b (c+d x)^m \sinh (e+f x)+3 a b^2 (c+d x)^m \sinh ^2(e+f x)+b^3 (c+d x)^m \sinh ^3(e+f x)\right ) \, dx\\ &=\frac {a^3 (c+d x)^{1+m}}{d (1+m)}+\left (3 a^2 b\right ) \int (c+d x)^m \sinh (e+f x) \, dx+\left (3 a b^2\right ) \int (c+d x)^m \sinh ^2(e+f x) \, dx+b^3 \int (c+d x)^m \sinh ^3(e+f x) \, dx\\ &=\frac {a^3 (c+d x)^{1+m}}{d (1+m)}+\frac {1}{2} \left (3 a^2 b\right ) \int e^{-i (i e+i f x)} (c+d x)^m \, dx-\frac {1}{2} \left (3 a^2 b\right ) \int e^{i (i e+i f x)} (c+d x)^m \, dx-\left (3 a b^2\right ) \int \left (\frac {1}{2} (c+d x)^m-\frac {1}{2} (c+d x)^m \cosh (2 e+2 f x)\right ) \, dx+\left (i b^3\right ) \int \left (\frac {3}{4} i (c+d x)^m \sinh (e+f x)-\frac {1}{4} i (c+d x)^m \sinh (3 e+3 f x)\right ) \, dx\\ &=\frac {a^3 (c+d x)^{1+m}}{d (1+m)}-\frac {3 a b^2 (c+d x)^{1+m}}{2 d (1+m)}+\frac {3 a^2 b e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {f (c+d x)}{d}\right )}{2 f}+\frac {3 a^2 b e^{-e+\frac {c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {f (c+d x)}{d}\right )}{2 f}+\frac {1}{2} \left (3 a b^2\right ) \int (c+d x)^m \cosh (2 e+2 f x) \, dx+\frac {1}{4} b^3 \int (c+d x)^m \sinh (3 e+3 f x) \, dx-\frac {1}{4} \left (3 b^3\right ) \int (c+d x)^m \sinh (e+f x) \, dx\\ &=\frac {a^3 (c+d x)^{1+m}}{d (1+m)}-\frac {3 a b^2 (c+d x)^{1+m}}{2 d (1+m)}+\frac {3 a^2 b e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {f (c+d x)}{d}\right )}{2 f}+\frac {3 a^2 b e^{-e+\frac {c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {f (c+d x)}{d}\right )}{2 f}+\frac {1}{4} \left (3 a b^2\right ) \int e^{-i (2 i e+2 i f x)} (c+d x)^m \, dx+\frac {1}{4} \left (3 a b^2\right ) \int e^{i (2 i e+2 i f x)} (c+d x)^m \, dx+\frac {1}{8} b^3 \int e^{-i (3 i e+3 i f x)} (c+d x)^m \, dx-\frac {1}{8} b^3 \int e^{i (3 i e+3 i f x)} (c+d x)^m \, dx-\frac {1}{8} \left (3 b^3\right ) \int e^{-i (i e+i f x)} (c+d x)^m \, dx+\frac {1}{8} \left (3 b^3\right ) \int e^{i (i e+i f x)} (c+d x)^m \, dx\\ &=\frac {a^3 (c+d x)^{1+m}}{d (1+m)}-\frac {3 a b^2 (c+d x)^{1+m}}{2 d (1+m)}+\frac {3^{-1-m} b^3 e^{3 e-\frac {3 c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {3 f (c+d x)}{d}\right )}{8 f}+\frac {3\ 2^{-3-m} a b^2 e^{2 e-\frac {2 c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {2 f (c+d x)}{d}\right )}{f}+\frac {3 a^2 b e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {f (c+d x)}{d}\right )}{2 f}-\frac {3 b^3 e^{e-\frac {c f}{d}} (c+d x)^m \left (-\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {f (c+d x)}{d}\right )}{8 f}+\frac {3 a^2 b e^{-e+\frac {c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {f (c+d x)}{d}\right )}{2 f}-\frac {3 b^3 e^{-e+\frac {c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {f (c+d x)}{d}\right )}{8 f}-\frac {3\ 2^{-3-m} a b^2 e^{-2 e+\frac {2 c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {2 f (c+d x)}{d}\right )}{f}+\frac {3^{-1-m} b^3 e^{-3 e+\frac {3 c f}{d}} (c+d x)^m \left (\frac {f (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {3 f (c+d x)}{d}\right )}{8 f}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(2639\) vs. \(2(543)=1086\).
time = 18.52, size = 2639, normalized size = 4.86 \begin {gather*} \text {Result too large to show} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \left (d x +c \right )^{m} \left (a +b \sinh \left (f x +e \right )\right )^{3}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.12, size = 385, normalized size = 0.71 \begin {gather*} \frac {3}{2} \, {\left (\frac {{\left (d x + c\right )}^{m + 1} e^{\left (\frac {c f}{d} - e\right )} E_{-m}\left (\frac {{\left (d x + c\right )} f}{d}\right )}{d} - \frac {{\left (d x + c\right )}^{m + 1} e^{\left (-\frac {c f}{d} + e\right )} E_{-m}\left (-\frac {{\left (d x + c\right )} f}{d}\right )}{d}\right )} a^{2} b - \frac {3}{4} \, {\left (\frac {{\left (d x + c\right )}^{m + 1} e^{\left (\frac {2 \, c f}{d} - 2 \, e\right )} E_{-m}\left (\frac {2 \, {\left (d x + c\right )} f}{d}\right )}{d} + \frac {{\left (d x + c\right )}^{m + 1} e^{\left (-\frac {2 \, c f}{d} + 2 \, e\right )} E_{-m}\left (-\frac {2 \, {\left (d x + c\right )} f}{d}\right )}{d} + \frac {2 \, {\left (d x + c\right )}^{m + 1}}{d {\left (m + 1\right )}}\right )} a b^{2} + \frac {1}{8} \, {\left (\frac {{\left (d x + c\right )}^{m + 1} e^{\left (\frac {3 \, c f}{d} - 3 \, e\right )} E_{-m}\left (\frac {3 \, {\left (d x + c\right )} f}{d}\right )}{d} - \frac {3 \, {\left (d x + c\right )}^{m + 1} e^{\left (\frac {c f}{d} - e\right )} E_{-m}\left (\frac {{\left (d x + c\right )} f}{d}\right )}{d} + \frac {3 \, {\left (d x + c\right )}^{m + 1} e^{\left (-\frac {c f}{d} + e\right )} E_{-m}\left (-\frac {{\left (d x + c\right )} f}{d}\right )}{d} - \frac {{\left (d x + c\right )}^{m + 1} e^{\left (-\frac {3 \, c f}{d} + 3 \, e\right )} E_{-m}\left (-\frac {3 \, {\left (d x + c\right )} f}{d}\right )}{d}\right )} b^{3} + \frac {{\left (d x + c\right )}^{m + 1} a^{3}}{d {\left (m + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.11, size = 899, normalized size = 1.66 \begin {gather*} \frac {{\left (b^{3} d m + b^{3} d\right )} \cosh \left (\frac {d m \log \left (\frac {3 \, f}{d}\right ) - 3 \, c f + 3 \, d \cosh \left (1\right ) + 3 \, d \sinh \left (1\right )}{d}\right ) \Gamma \left (m + 1, \frac {3 \, {\left (d f x + c f\right )}}{d}\right ) - 9 \, {\left (a b^{2} d m + a b^{2} d\right )} \cosh \left (\frac {d m \log \left (\frac {2 \, f}{d}\right ) - 2 \, c f + 2 \, d \cosh \left (1\right ) + 2 \, d \sinh \left (1\right )}{d}\right ) \Gamma \left (m + 1, \frac {2 \, {\left (d f x + c f\right )}}{d}\right ) + 9 \, {\left ({\left (4 \, a^{2} b - b^{3}\right )} d m + {\left (4 \, a^{2} b - b^{3}\right )} d\right )} \cosh \left (\frac {d m \log \left (\frac {f}{d}\right ) - c f + d \cosh \left (1\right ) + d \sinh \left (1\right )}{d}\right ) \Gamma \left (m + 1, \frac {d f x + c f}{d}\right ) + 9 \, {\left ({\left (4 \, a^{2} b - b^{3}\right )} d m + {\left (4 \, a^{2} b - b^{3}\right )} d\right )} \cosh \left (\frac {d m \log \left (-\frac {f}{d}\right ) + c f - d \cosh \left (1\right ) - d \sinh \left (1\right )}{d}\right ) \Gamma \left (m + 1, -\frac {d f x + c f}{d}\right ) + 9 \, {\left (a b^{2} d m + a b^{2} d\right )} \cosh \left (\frac {d m \log \left (-\frac {2 \, f}{d}\right ) + 2 \, c f - 2 \, d \cosh \left (1\right ) - 2 \, d \sinh \left (1\right )}{d}\right ) \Gamma \left (m + 1, -\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) + {\left (b^{3} d m + b^{3} d\right )} \cosh \left (\frac {d m \log \left (-\frac {3 \, f}{d}\right ) + 3 \, c f - 3 \, d \cosh \left (1\right ) - 3 \, d \sinh \left (1\right )}{d}\right ) \Gamma \left (m + 1, -\frac {3 \, {\left (d f x + c f\right )}}{d}\right ) - {\left (b^{3} d m + b^{3} d\right )} \Gamma \left (m + 1, \frac {3 \, {\left (d f x + c f\right )}}{d}\right ) \sinh \left (\frac {d m \log \left (\frac {3 \, f}{d}\right ) - 3 \, c f + 3 \, d \cosh \left (1\right ) + 3 \, d \sinh \left (1\right )}{d}\right ) + 9 \, {\left (a b^{2} d m + a b^{2} d\right )} \Gamma \left (m + 1, \frac {2 \, {\left (d f x + c f\right )}}{d}\right ) \sinh \left (\frac {d m \log \left (\frac {2 \, f}{d}\right ) - 2 \, c f + 2 \, d \cosh \left (1\right ) + 2 \, d \sinh \left (1\right )}{d}\right ) - 9 \, {\left ({\left (4 \, a^{2} b - b^{3}\right )} d m + {\left (4 \, a^{2} b - b^{3}\right )} d\right )} \Gamma \left (m + 1, \frac {d f x + c f}{d}\right ) \sinh \left (\frac {d m \log \left (\frac {f}{d}\right ) - c f + d \cosh \left (1\right ) + d \sinh \left (1\right )}{d}\right ) - 9 \, {\left ({\left (4 \, a^{2} b - b^{3}\right )} d m + {\left (4 \, a^{2} b - b^{3}\right )} d\right )} \Gamma \left (m + 1, -\frac {d f x + c f}{d}\right ) \sinh \left (\frac {d m \log \left (-\frac {f}{d}\right ) + c f - d \cosh \left (1\right ) - d \sinh \left (1\right )}{d}\right ) - 9 \, {\left (a b^{2} d m + a b^{2} d\right )} \Gamma \left (m + 1, -\frac {2 \, {\left (d f x + c f\right )}}{d}\right ) \sinh \left (\frac {d m \log \left (-\frac {2 \, f}{d}\right ) + 2 \, c f - 2 \, d \cosh \left (1\right ) - 2 \, d \sinh \left (1\right )}{d}\right ) - {\left (b^{3} d m + b^{3} d\right )} \Gamma \left (m + 1, -\frac {3 \, {\left (d f x + c f\right )}}{d}\right ) \sinh \left (\frac {d m \log \left (-\frac {3 \, f}{d}\right ) + 3 \, c f - 3 \, d \cosh \left (1\right ) - 3 \, d \sinh \left (1\right )}{d}\right ) + 12 \, {\left ({\left (2 \, a^{3} - 3 \, a b^{2}\right )} d f x + {\left (2 \, a^{3} - 3 \, a b^{2}\right )} c f\right )} \cosh \left (m \log \left (d x + c\right )\right ) + 12 \, {\left ({\left (2 \, a^{3} - 3 \, a b^{2}\right )} d f x + {\left (2 \, a^{3} - 3 \, a b^{2}\right )} c f\right )} \sinh \left (m \log \left (d x + c\right )\right )}{24 \, {\left (d f m + d f\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (a+b\,\mathrm {sinh}\left (e+f\,x\right )\right )}^3\,{\left (c+d\,x\right )}^m \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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